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i need help
Develop a C-program that allows user: Adding a new employee Find data about employees using a name inputted. Remove an employee based on a code inputted Print the list in descending order based on salary + allowance.
3 ответов
+ 1
#include<Stdio.h>
#include <windows.h>
#include <string.h>
#define MAX 1000
int main(){
char codes[MAX][9];
char names[MAX][21];
double salaries[MAX];
double allowances[MAX];
}
char getUserChoice()
{
int c;
printf("1-Add new employee\n");
printf("2-Find data using name inputted\n");
printf("3-Remove employee\n");
printf("4-Print the list in descending order based on salary + allowance.\n");
printf("5-Quit\n");
printf("Choice = ");
fflush(stdin);
scanf("%c", &c);
return c;
}
void add (char codes[][9],char names[][21], double salaries[], double allowances[], int*pn)
{
char name[21];
int i, existed;
do {
printf("Add a employee: ");
fflush(stdin);
scanf("%20[^\n]", names);
existed = 1;
for ( i = 0; i < *pn; i++)
if (strcmp(names,list[i]) == 0)
{
printf("Name existed!Retype!\n");
existed = 0;
i = *pn - 1;
}
} while (!existed);
strcpy(list[*pn], names);
(*pn)++;
printf("Added!\n");
system("pause");
system("cls");
}
void printBasedName( char name[], char codes[][9],char names[][21], double salaries[], double allowances[], int n)
{
int i;
printf("Searching for : ");
char hs[21];
fflush(stdin);
scanf("%20[^\n]", &hs);
for (i = 0; i < *pn; i++)
{
nameStr(hs);
nameStr(list[i]);
char * ptr = strstr(list[i], hs);
if (ptr != '\0') printf("RESULT : Name[%d] : %s\n", i, list[i]);
}
}
void removePos (int pos, char codes[][9],char names[][21], double salaries[], double allowances[], int *pn)
{
search(list, pn);
printf("Which Name you want to removed?(input a number) : ");
int del, i;
scanf("%d", &del);
if (del >= 0 && del < *pn) {
for (i = del + 1; i < *pn; i++)
strcpy(list[i-1], list[i]);
printf("Removed!\n");
(*pn)--;
} else printf("UnRemoved!\n");
system("pause");
system("cls");
}
void sort(char codes[][9], char names[][21], double salaries[],
double allowances[], int n)
{ for (i=
+ 1
it not work
0
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