How this code run to convert from decimal to hexa

Question

s=""
h=[str(i) fot i in range(10)]+["A","B","C","D","E","F"]
while dec :
s+=h[dec%16]
dec//=16
hexsa = [::-1]
print (hexsa)

Answer 1

stanislav| yes dec variable stored a decimal number , i dont write it here
😅

Answer 2

yes you are right it should be // couse i wrote it in mobile i didn't pay attention .. the output true case 10000000 in binary equal 80 in hexa but 129 in decimal

Answer 3

binary = input("Enter a digit in binary:")
dec=0
length = len (binary)-1
for i in binary :
integer = int(i)
dec += integer *2**length
length -=1

h = [ str (i) for i in range (10)] + [ "A","B","C","D","E","F"]
s=""
while dec:
s+=h[dec%16]
dec\\=16
hexa = s[::-1]

print(hexa)

these is the full code to convert from binary to hexa

Answer 4

when i wrote the full code again , i mentioned that the code to convert from binary to hexa 😅 , i don't understand the while loop , can u help?

Answer 5

What is dec variable? it is not defined

Answer 6

Post full code, please :)

Answer 7

I guess that the main mistake "\\" in dec\\=16 . Should be "//", no?
Enter a digit in binary:10000000
80
But logic of program is wrong, answer should be 127 as I remember in my example

Answer 8

Sorry, it seems like it works fine, I just was confused, because topic sounds like How this code run to convert from decimal to hexa, but program asking for binary. So, it seems like it works ! Good job! :)