How to perform equality check on chars

Question

I'm trying to perform an equality check on chars based on user input but I always get an Error when I try this. This is just a sample code of what I'm talking about

char opp[1];

scanf("%c",opp);
if(opp == 'c')
{
printf("hello");
}
But I always get an Error on that if statement
Thanks in advance

Answer 1

no need char array..
Just put
char opp;

Answer 2

Thanks but I'm hit with segmentation fault

Answer 3

Also You need &opp for taking char... Chidera

char opp;

scanf("%c",&opp);
if(opp == 'c')
{
printf("hello");
}

Answer 4

I suggest you use a single char, not char[], but I assume you are asking "What if I use char[1]?", the reason why you get an error is that when you make it char[], opp is the same as '&opp[0]', so your scanf is fine since opp can be said as &opp[0]. However, your if is wrong, you are trying to compare a constant char with an address of opp[0], instead, try 'if (*opp == 'c')', that way, you are comparing a pointer that points to a character with a character.