Hi guys,somebody can help

Question

someone can explain why it doesn’t work,the program is i must write 5 figures (negative and positive) and it must find how many positive and negative,need it do through the FOR and arrays,whats wrong?

#include <stdio.h>

int main()
{
int a[5] = {5,4,3,2,1}, sumPos = 0, sumNeg = 0;
//printf("Vvedit pershe chuslo:”);
//scanf("%d", &a[i]);
for (int i = 0; i < 5; i++)
{
if (a[i] < 0)
sumNeg = +a[i];
else
sumPos = +a[i];
}
printf("Suma negative numbers: %d\n", sumNeg);
printf("Suma positive numbers: %d", sumPos);
return 0;
}

Answer 1

If you are trying to count how many positive and negative numbers there are, instead of finding the sum, then change it to

if (a[i] < 0)
sumNeg += 1;
else
sumPos += 1;

Answer 2

Thank you guys very much
everyone helped!!!!💪🏻🙏🏻

Answer 3

it is working correct!

Answer 4

it didn’t help

Answer 5

i must write negative and positive figures by myself in console ,a then get a how many negative and positive

Answer 6

i dont need that console write 0 and 15 by itself

Answer 7

it works now but show in console suma istead of numbers

Answer 8

If your goal is to count how many positive numbers or negative numbers are in the array you just need to increment your sumNeg or sumPos given your if conditions.
The code will be :

#include <stdio.h>

int main()
{
int a[5] = {5,-1,3,2,1}, sumPos = 0, sumNeg = 0;

for (int i = 0; i < 5; i++)
{
if (a[i] < 0)
sumNeg += 1;
else
sumPos +=1;
}
printf("Suma negative numbers: %d\n", sumNeg);
printf("Suma positive numbers: %d", sumPos);
return 0;
}