How to make it work?

Question

i have a task to count the longest streak of ascending numbers:
1 2 3 4 -> streak of 4
1 2 3 4 2 3 4 5 6 -> longest streak is 5 (2 3 4 5 6)

so i have one problem, the problem is that when i "break" the streak with a lower number then the one before, and then starting to build a larger streak - it wont count in the streak the first number that "broke" the last streak - cuz it just resets the streak...
example: 1 2 3 4 5 4 5 6 7 8 9 -> outputs 5 instead of 6.
(btw, the input will stop when entering 999 or -1)

my code:

import java.util.*;
public class Main
{
public static void main(String[] args)
{

Scanner scan = new Scanner(System.in);

System.out.println("Enter Percent:");
double percent = scan.nextDouble();

int streak = 0;
int maxStreak = streak;
double max = 0;

while(percent != -1 && percent != 999){

if (percent > max){
max = percent;
streak++;
}

if (percent < max){
streak = 0;
max = 0;
}

if (streak > maxStreak){
maxStreak = streak;
}

System.out.println("Enter Percent:");
percent = scan.nextDouble();

}

System.out.println("Longest Streak of days with high percentage: " + maxStreak);

}
}

Answer 1

Reset to 1 streak. The current number is also started streak.
streak = 1 ;

Answer 2

Yahel
No. I mean reset in :
if(percent <max) {
streak=1;
max = 0;
}

Answer 3

Oh.
Set max = percent ; also..

Yahel
if(percent <max) {
streak=1;
max = percent;
}

Actually make it as else part. Then I think it works better...

Answer 4

Jayakrishna🇮🇳 so if I do 1 2 3 4 it will give me 5 instead of 4. So at the end- should I subtract the streak by 1?

Answer 5

Jayakrishna🇮🇳 , but now if I do that: 6 5 4 -> it outputs 2.