I was wondering is the display function wrong when I call the search function?

Question

When it get the answer for the question in search function my compiler still print out both of the function i don’t know why

int search(string arr[ROW][COLUMN], string STR)
{

for (int i=0; i<ROW; i++)
{
if (arr[i][0]==STR)
{
cout <<"Answer for the question: " <<arr[i][1] << endl;
return i;
}
}
return -1;
}

void display (string STR)
{
string arr[ROW][COLUMN];
int match= search(arr, STR);
if (match == -1)
{
cout << "Please enter a choice from below\n";
//code for choice
}
}

Answer 1

You declared arr[][] as int array and function defination has string arr[][], it should display error..
And what are the values to array, not mentioned there, how you storing..
And your while loop is infinite loop, no exit condition. Instead use
if(match== -1){
..
}

Answer 2

Assign the values to string array arr. Then call search function. Otherwise it is empty array and return -1 only...

Edit :

Skylar Yang that row and column index values..
What and where is the values for
arr[0][0],arr[0][1],
arr[1][0],arr[1][1],
.......
.......
arr[99][0],arr[99][1]

Answer 3

You didn't initialize the arr in display() with size.

Answer 4

oops sorry i write the wrong code I updated the code again

Answer 5

I use const int ROW=100 and const int COLUMN =2 in declaration Jayakrishna🇮🇳

arr[0][0] to arr[99][0] will be the input file for question
arr[0][1] to arr[99][1] will be the input file for answer