What is output of the 👇 code

Question

Give answer in detail how it comes

If you like code upvote me

https://code.sololearn.com/c7QWOPAmVgJP/?ref=app

Answer 1

You're welcome,
And it is good question BTW
Stay curious 👍

Answer 2

It becomes easier to read and understand if you put spaces in between

printf("%d \n", a++ + b);

`a++` is post-increment operation, meaning it does not take effect immediately, until statement end (semicolon), or another post/pre increment is applied to variable <a>.

But mixing up access and modification to a certain data in one statement is not such good idea.

Answer 3

But it canbe like : a + ++b
How can you say it must be like
a++ + b

Answer 4

Excuse me, when did I say it *must be* like `a++ + b`?

You will get different result if you write `a + ++b` because this way pre-increment operator is applied on variable <b>.

The way your code was written (`a+++b`) compiler will take it as `a++ + b` because operator precedence plays a role there

https://en.cppreference.com/w/c/language/operator_precedence

Answer 5

Sorry for this
But when try to compile it always give answer 7
So my question is that why compiler read it as a++ + b why not a + ++b

Answer 6

It's because post-increment operator has higher precedence (priority) opposed to pre-increment operator. Read the linked page to see clearly.

Answer 7

Ok thank you