#include <stdio.h> int main() { int c=50; for(;c;) c--; printf ("c=%d",c); return 0; }

Question

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Answer 1

Pls clarify your question, Pls add a code playground, so peope can help you simply, but clarify your question.
Add relevant tags to the question too.
Thank you.

Answer 2

c=0, because you decrease it in loop and when item become 0, loop finished!

Answer 3

According to your given information about this code ,
I found that here in output,
c=0
Reason: because in your code you decremented the value of c .
And when the value of c become 0 , then we came out of the loop.
Hence , the value of c came as 0 in output.