Solo learn Password validate must be build as the nested conditional. There are 3 main requitement: the password string must co

Question

must be build as the nested conditional. There are 3 main requitements: the password string must contain minimum 2 digit decimal number in password string. If so, next it must contain minimum 2 of 7 special characters determined. If the nd requirements is fulfilled, last we have to test if it's length is between 7 and 14 characters in length (add 1 to include '\0 because I use c-style pointer based string or array of characters. Please show me the requirements of test case 5,7,9 do I can modify it accordingly to predetermined conditions.
https://www.sololearn.com/discuss/2655876/?ref=app

Answer 1

Guys what about C# and ruby

Answer 2

Oliver Pasaribu See this code (yours)

I noticed that there is no validation of special characters and by the way, it seems like your answer of your first part of your code had been cut or not complete maybe because of character limits in comments in Q&A.

Anyway here's the code, please update me it is still not solved. Thanks.

https://code.sololearn.com/c6wiA2slBbF6/?ref=app

Answer 3

Yes, test cases are hidden even if you purchase pro. But the first and second test cases are not hidden right? Then please send the two sample input and output of the first two test cases (test case1 and test case2).

And is that from Code Coach?
If that is from code coach, try this:
https://code.sololearn.com/crsnRg8p7o0Q/?ref=app

Answer 4

did you try length > 7 && length < 14 ?

Answer 5

It seems that nothing is wrong about the validation, I think the issue here is about the length of the string cause 3 test cases were not passed (just possible).
(1) Can you specify what '/0' means?
(2) Can you give some sample Inputs and Outputs?
Thanks

Answer 6

Nicko12, amazing the code passes all 14 test cases from solo learn. I try to observe the difference to the earlier code, the main different is int length = strlen(password) and not length = strlen(password) -1. My code exclude null terminating character.

Answer 7

I have different opinion. I used to work or in touch with digital logic, that's why I prefer boolean-flag to direct if multi condition. We use boolean functions following c++ is-family functions which utilized flag of condition or marker widely.

Answer 8

OK. Thank you very much niko12 from Philippines. I need to check it later to convince or to ensure the for counter since I did not use '\0'null terminating char as loop termination controller.

Answer 9

/* Nested if and single if statement with 2 condition combine with operator && gives equal result.

it only show simplicity and level of creativitu of programmer. please look carefully to this following nested if and single if with 2 condition combined with && operator

#include <iostream>
using namespace std;

int main() {
int a=1;
int b=2;

if (a==1)
{
if (b==2)
{
cout<<a<<endl;
cout<<b<<endl;
}
else return -1;
}
else return -1;

if ( (a==1) && (b==2) )
{
cout<<a<<endl;
cout<<b<<endl;
}

return 0;
}

Answer 10

Oliver Pasaribu Yeah that was the thing (length of string) I was talking about earlier and just a suggestion, those bool data types are quite not important on short codes, I think it can be just compare it right away. And it turns out that the string must be greater than 7 and not less than 14.

Anyway, you're Welcome🙂👍

Answer 11

Oliver Pasaribu Yes, I agree that it is a good practice and I just simplified it cause I'm still a beginner in c++, anyway maybe I'll do that too in my future c++ codes. Thanks.

Answer 12

Inq

Answer 13

Part 1 of my code Password Validator

#include <iostream>
#include <string>
#include <cstring>
using namespace std;

int main() {
char password[13];
int length;
bool is_length_valid=0;
bool is_digit_valid=0;
bool is_special_character_valid=0;
bool is_password_valid=0;
int digitcount=0;
int specialcharactercount=0;

//cout<<"Please enter your password:";
cin>>password;
length = strlen(password)-1;
// exclude '\0' terminated character

char *ptr;
ptr = password;

// validate if the password contains
// at least 2 numerical characters
for(int i=0; i<=length; i++)
{if (isdigit(password[i]))
++digitcount;}

// validation the presence of minimun 2
// special characters in the string
if (digitcount>=2)
is_digit_valid = 1;
else
is_digit_valid = 0;

// validation the presence of minimun 2
// special characters in the string
if (is_digit_valid==1)
{
for(int i=0; i<=length; i++)
{
if (
// using pointer arithnatics
*(ptr+i) == '!' ||
*(ptr+i) == '@' ||
*(

Answer 14

Part 2 of my code Password Validator

// validate length of password is
// between 7<=length<=14 characters
if (is_special_character_valid)
{
if (length>=7 && length<=14)
is_length_valid = 1;
else
is_length_valid = 0;
}

if (is_length_valid )
is_password_valid = 1;
else
is_password_valid = 0;

if (is_password_valid)
cout<<"Strong"<<endl;
else
cout<<"Weak"<< endl;
return 0;
}

Answer 15

Sure. The length flagged by bool function is_length_valid return true if (length >=7 && length <=14). Or you can modify the if clause if (length >6 && length <15). variable into length=strlen(password)-1 to exclude character '\0'

Answer 16

This is part of code validates presenence of special characters

// validation the presence of minimun 2
// special characters in the string
if (is_digit_valid==1)
{
for(int i=0; i<=length; i++)
{
if (
// using pointer arithnatics
*(ptr+i) == '!' ||
*(ptr+i) == '@' ||
*(ptr+i) == '#' ||
*(ptr+i) == '#x27; ||
*(ptr+i) == '%' ||
*(ptr+i) == '&' ||
*(ptr+i) == '*'
)// end if comparison
++specialcharactercount;
} // end for looping

if (specialcharactercount>=2)
is_special_character_valid =1;
else
is_special_character_valid =0;
} // end of is_digit_valid

Answer 17

My code does not pass solo learn test case number 5 and 7 or 5 and 9. I don't know what requirement expected from test case 5 and 7? But the requirements doesn't clearly mention if we must use nested if to test the overall conditions or. We can also use if (is_digit_valid && is_special_character_valid && is_length_valid) then password_valid = true;

Answer 18

I am not using solo learn pro.

Answer 19

Hi Nicko12 if I don't bother you, could you please assist me to solve the problem related to Queue Management part 2. The instruction said we have to overload operator + to enable us do operation q[n] = q[a] + q[b] ; a, b, n are constant integers or array index or array subscript. The queue itself is implemented using dynamic array using internet * queue point to heap and allocates memory for n into values.

Answer 20

Oliver Pasaribu I think I have not yet solved that problem but I will try to look at it and try to solve if I can. Although I suggest/recommend to post a new question about this, and show your attempt so other people that are way better than me can also help. 😊