+ 1

JS 7.2 Exercise help

Hello, Can anyone help me with what I am doing wrong here... I have tried multiple solutions and every one has failed. It asks to output what the price would be with 20% off so I am multiplying the number times 80%(.8). I have tried return, output and console.log and none have worked for me. —- EXERCISE BELOW —— //so we don’t overwhelm you, we’ve hidden the code that executes the input function main() { var oldPrice = parseInt(readLine(), 10); // your code goes here //my code.... var newPrice = (oldPrice * .8); } //my code... console.log(main(newPrice));

8th Jan 2021, 9:35 PM
KfMand08
KfMand08 - avatar
5 ответов
0
Nevermind, I just found out that I need to put the “console.log” inside the curly braces instead of outside.
8th Jan 2021, 9:49 PM
KfMand08
KfMand08 - avatar
0
You're calling a main function which has no parameter and at the same time invoking it with argument (newPrice) which is not define. See the correct simple version of it below: function main() { var oldPrice = parseInt(readLine(), 10); // your code goes here //my code.... var newPrice = (oldPrice * .8); return newPrice; } //my code... console.log(main()); Can you see the differences? Note: The newPrice you declared in your main function is a local scope. That's why the newPrice is not define when you try to pass it as an argument to the main function which too has no parameter. Hope it helps?
8th Jan 2021, 10:40 PM
Fabala Dibbasey
Fabala Dibbasey - avatar
0
send me that version if you won't mind please
8th Jan 2021, 10:51 PM
Fabala Dibbasey
Fabala Dibbasey - avatar
0
This is what I had submitted and it worked... //so we don’t overwhelm you, we’ve hidden the code that executes the input function main() { var oldPrice = parseInt(readLine(), 10) // your code goes here var newPrice = (oldPrice * .8) console.log(newPrice) }
9th Jan 2021, 4:02 AM
KfMand08
KfMand08 - avatar
0
Yeah this would work because newPrice is defined and you're not passing an argument to the main function when invoking it i.e main(); It's similar to my work on my first respond. The only different is I return instead of console.log
9th Jan 2021, 1:05 PM
Fabala Dibbasey
Fabala Dibbasey - avatar