“Snail in the well” help (JS)

Question

Hi All,
I am struggling a bit with this challenge, could someone help explain how to work this? After working on a few possibilities I am stuck because I am unsure how to separate the days into two for day and night for “+7” and “-2”. This one definitely has me stumped. Thank you for any help!

The snail climbs up 7 feet each day and slips back 2 feet each night.
How many days will it take the snail to get out of a well with the given depth?

Sample Input:
31

Sample Output:
6

Explanation: Let's break down the distance the snail covers each day:
Day 1: 7-2=5
Day 2: 5+7-2=10
Day 3: 10+7-2=15
Day 4: 15+7-2=20
Day 5: 20+7-2=25
Day 6: 25+7=32
So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night.

Answer 1

Thank you for your help!! Is “let” similar to “var”? I haven’t used that yet. I went back and forth through various loop options and ended with what you had used; “while.” I was confused by the “while (true)” part though because what part are you saying while it‘s true? I put in “whille(climb<depth)” to do the below, which it accepted but I just want to be sure the way I did it was accurate moving forward?

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var climb = 0;
var days = 0;
while (climb < depth) {
days++;
climb += 7;

if (climb >= depth){
break;
}

climb -= 2;
}

console.log(days);
}

Answer 2

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
let climbedDistance = 0;
for(days = 1; depth > climbedDistance; days++) {
climbedDistance += 7;
if(climbedDistance >= depth) console.log(days);
else climbedDistance -= 2;
}
}

So we just need to compare the distance the snail climbed and the depth of the well. We start with the day 1, increment the distance by 7 and start our comparison. In every iteration we check the condition (climbedDistance >= depth) until it becomes true and then log the accumulated number of days on the console. Easy, right?

Answer 3

function main(){
var depth = parseInt(readLine(),10);
var days = 0;
var feet = 0;

while(feet<depth){
++days;
feet +=7;

if(feet > depth -1){
break;
feet -=2;
}
console.log(days);
}

Answer 4

There's a pretty simple solution for this problem. On average the snake will climb 5 feet per day and will climb a maximum of 7 which is 2 more than 5.
This means we can subtract 2 from the distance and then divide by 5 to get the amount of days: (32 - 2) / 5 = 6
If you need to round you have to use Math.ceil() because for example 6.1 days don't work but instead you need whole 7 days to reach the distance.

Answer 5

let day = 1;
let climb = 7;
let depth = 32;

for (; climb < depth; climb +=7) {
day++;
if (climb === depth) {break;
} else {
climb = (climb - 2);
} };

console.log(day);

Answer 6

// easy solution
function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var
go = 7-2
var dist = 0
var day = 0
for(let go =5; dist<=depth-3; dist +=go){
day+=1

}
console.log(day)
}

Answer 7

function main() {
var depth = parseInt(readLine(), 10);
//tu código va aquí
var d = 0; // días
var c = 0; // caracol
while (c < depth) {
c += 7 - 2;
d += 1;
if (c > depth) {
if (c - 2 <= depth) {
console.log(d);
break;
}
else if (c > depth) {
console.log(d - 1);
break;
}
}
}
}

Answer 8

var day = Math.ceil((depth-2)/5);
Thats it!! Just output it....Thanks Aaron Eberhardt

Answer 9

var x = 0;
var day;

do{
x+=1;
day = Math.ceil((depth -2) /5);
}while(depth<=x); // or (depth < x);

console.log(day);

Answer 10

function main() {
var depth = parseInt(readLine(), 10);

var climb = 0;
var days = 0;

for (; climb < depth; days++){
climb += 7;
if(climb >= depth){
}else{
climb -=2;
}
}
console.log(days);
}

Answer 11

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
let day = 1;
for (climb = 7; climb < depth; climb +=5) {
day++;
while (climb === depth) {
break;
}
}
console.log(day);
}

Answer 12

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here

var days = 1;

for (climb=7; climb<depth; climb+=7)
{

climb-=2;

if (climb==depth){
break;
console.log(days);
}

else
days++

}

console.log(days);
}

Answer 13

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var climb = 7;
var slips = 2;
var distance = 0;
var days = 0;
while(distance < depth) {
if(distance >= depth - climb) {
distance = distance + climb;
days++;
console.log(days);
break;
} else {
distance = distance + climb - slips;
days++;
}
}
}

Answer 14

I still don't entirely understand why

climb -= 2

must come after the

break;

Can someone please explain?

Answer 15

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var snail = 0, day = 0;
while((snail + 2) < depth){
snail = snail+7-2;
day++;
}

console.log(day);
}

Answer 16

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var feet = 0;
for (i=1;;i++){
feet += 7;
if (feet >= depth)
break;
feet -= 2;
}

console.log(i)
}

Answer 17

Plz anyone can explain me that plz

Answer 18

Explanation :-
1.)
Let's break down the distance the snail covers each day:
Day 1: 7-2=5
Day 2: 5+7-2=10
Day 3: 10+7-2=15
Day 4: 15+7-2=20
Day 5: 20+7-2=25
Day 6: 25+7=32
So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night.

OR

2.)
On average the snake will climb 5 feet per day and will climb a maximum of 7 which is 2 more than 5.
This means we can subtract 2 from the distance and then divide by 5 to get the amount of days: (32 - 2) / 5 = 6
If you need to round you have to use Math.ceil() because for example 6.1 days don't work but instead you need whole 7 days to reach the distance.

Answer 19

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var days = 0;

for (i=0; i<depth; i++){

// on average it takes 5 days to climb. we get the absolute value of the division between the depth and 5
days = ~~(depth / 5);

// if the remainder of the division is greater than 2 then the snail will slip back thus we add an extra day
if((depth % 5) >2){
days +=1
}

}

console.log(days)
}

Answer 20

function main() {
var depth = parseInt(readLine(), 10);
//tu código va aquí
var d = 0; // días
var c = 0; // caracol
while (c < depth) {
c += 7 - 2;
d += 1;
if (c > depth) {
if (c - 2 <= depth) {
console.log(d);
break;
}
else if (c > depth) {
console.log(d - 1);
break;
}
}
}
}