What the target output of activity explain the codes

Question

#include <chrono>
#include <iostream>
#include <stdlib.h>
#include <thread>
using namespace std;

bool flag [2];
int turn;
void P0()
{

while (true)
{
flag [0] = true;//declaring the desire to enter CS
turn = 1;//giving the chance to other process (P1)
while (flag [1] && turn == 1) /* wait for other process to exit CS and do nothing */;
//critical section simulation here
// let this function work for something(nothing) for 5 seconds
cout<<"Process 0 is in critical section for 3 seconds"<<endl;
for (int i=1; i<=3; i++)
{
std::this_thread::sleep_for(std::chrono::seconds(1));
cout<<"Process 0 on CS [Timer]: "<<i<<endl;
}

flag [0] = false;
cout<<"Process 0 is in remainder section \n\n";
}
}

//same structure as P0
void P1()
{
while (true)
{

flag [1] = true;
turn = 0;
while (flag [0] && turn == 0) ;
//critical section simulation here
// let this function work for something(nothing) for 5 seconds
cout<<"Process 1 is in critical section for 5 seconds"<<endl;
for (int j=1; j<=5; j++)
{
std::this_thread::sleep_for(std::chrono::seconds(1));
cout<<"Process 1 on CS [Timer]: "<<j<<endl;
}

flag [1] = false;
cout<<"Process 1 is in remainder section \n\n";

}
}

int main()
{
flag [0] = false;
flag [1] = false;

//run two threads here
// one for P0 and another for P1
std::thread thr1, thr2; //declaring threads
thr1= std::thread(P0); //P0 will be thr1
thr2= std::thread(P1); //P1 will be thr2

//thr1 and thr2 will join in the main function
thr1.join();
thr2.join();
return 0;
}

Answer 1

that allows two or more processes to share a single-use resource without conflict, using only shared memory for communication.

https://en.m.wikipedia.org/wiki/Peterson%27s_algorithm