neend help in following code

Question

The snail climbs up 7 feet each day and slips back 2 feet each night.
How many days will it take the snail to get out of a well with the given depth?

Sample Input:
31

Sample Output:
6

Explanation: Let's break down the distance the snail covers each day:
Day 1: 7-2=5
Day 2: 5+7-2=10
Day 3: 10+7-2=15
Day 4: 15+7-2=20
Day 5: 20+7-2=25
Day 6: 25+7=32
So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night.
My Attempt😁😬
function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
for (k=5; k<=depth; k++ ){
console.log(k+=5)
}
}

Answer 1

i think this will work too
let output = Math.ceil((input - 2) / 5);
this is O(1) i believe..so it should be faster

Answer 2

Hello Bilal Ahmad in your code you're not counting the days.
Also, for loop is not the best choice here in my opinion.

Check this out...
function main() {
var depth = 31, day = 0, k = 0;
//your code goes here
while(k<=depth){
day++; // how many days gone already
k+=7; // climbs up by 7
//check if the snail has reach the well or not
if(k>=depth){
break;
}
k-=2; // slips down by 2
}
console.log(day);
}
main();