Python pull the trigger

Question

EDIT: I’ve made progress but again I’m stuck

Here is the question I’m stuck on

You are making a game! The player tries to shoot an object and can hit or miss it.
The player starts with 100 points, with a hit adding 10 points to the player’s score, and a miss deducting 20 points.

Your program needs to take 4 action results as input ("hit" or "miss"), calculate and output the player’s remaining points.

Sample Input
hit
hit
miss
hit

Sample Output
110

Explanation: 3 hits add 30 points, one miss deducts 20, making the total points equal to 110.

Here is my code so far it seems to work on Pycharm on my laptop but not quite right, definitely doesn’t pass the the little quiz on the app though

score = 100
tries = 4
while tries >= 0:
if input() == "miss":
print("miss")
score -= 20
print(score)
if input() == "hit":
print("hit")
score += 10
print(score)
tries -= 1

I feel like I’m missing something obvious, again a dumbed down push in the right direction is so helpful

Answer 1

Hey James, youre pretty close! just need your input() variable inside of your while loop. You probably also need tries to be greater than (but not equal to) 0. here is an example of my working code:

shots = 4
score = 100

while shots > 0:
result = input()
if result == "hit":
score +=10
shots -=1
elif result == "miss":
score -=20
shots -=1
print(score)

Answer 2

Hey Carolina, imagine this is a script and we’re only running through the code one time. If that’s the case and the input was outside of the loop, we would get input one time and the while loop would take that single input and use it every time it loops. If we put the input variable inside the while loop, we are accepting new input multiple times in the script since the while loop keeps asking for additional input. I hope that helps make it make sense, TL;DR is just that we need the variable to change each time the while loop runs.

Answer 3

I fixed my code after Drew Roberts comment saying that the input variable should be inside the while loop, but I can't see why it's like that... Why it couldn't be outside the while loop?

Answer 4

Ohh i got it now! Thank you very much Drew :)

Answer 5

if input() is equal to "hit" then add 10 to score otherwise add 20 to score if input is equal to "miss"

Answer 6

Try this bruh

shots = 1
score = 100
while shots <= 4 :
atau = input()
if atau == "miss" :
score = score - 20
shots += 1
else :
score = score + 10
shots += 1
print (score)

Answer 7

Could someone explain why the input should be inside while loop, please? Thanks :)

Answer 8

Hello James I'm here to help you and you should put the variable I = 1 or no according you want to either variable or 1 directly and do not forget the count even the program doesn't print to infinite.

score = 100
tries = 4
i = 1
while i<=tries:
result = input("Enter hit or miss: ")
if result == 'hit':
print("hit")
score += 10
print("score = " + str(score))
elif result == 'miss':
print("miss")
score -= 20
print("score = " + str(score))
i += 1

output:

Enter hit or miss: hit
hit
score = 110
Enter hit or miss: hit
hit
score = 120
Enter hit or miss: hit
hit
score = 130
Enter hit or miss: hit
hit
score = 140

Answer 9

sum = 0
while True:
x = input()
if x == "stop":
break
else:
sum += int(x)
print(sum)

Answer 10

my working code
points=100
action=1

while action <=4:
result =input()
action+=1
if result == "hit":
points+=10
if result == "miss":
points-=20

print(points)

Answer 11

Heyo, not sure if you already got this answered but i just wanted to make sure you knew that you’re only supposed to print the score once at the end of the loop.
Fixing that along with making one of those if statements an elif (like Abhay hinted at) should do the trick!

Answer 12

Here's my code

score = 100
action = input()

#4 tries
tries = 4
while tries >=0:
if action == "miss":
score += 20
tries -= 1
elif action == "hit":
score += 10
tries -= 1

print(score)

For some reason everytime the output is 150 and I can't for the life of me work out why. I'm sure it's something simple....

Answer 13

Thank you so much for that. I have been pulling my hair out for ages.

Answer 14

here is mine: (ik its diffrent but it works rly well!!:))

sco = 100
sho = 1

while sho <= 4:
if input() == “hit”:
print(sco + 100)
else:
print(sho - 20)
sho+=1

Answer 15

I cant do it please help me.

Answer 16

My Correct code:

points=100
x=1
while x<5:
my_input=input()
if my_input=="hit":
points +=10
elif my_input=="miss":
points -=20
x=x+1
print(points)

Answer 17

Guy's want to post my code here and it works perfect:

points = 100
x = 1
while x <= 4:
my_input = input()
x = x + 1
if my_input == "hit":
points += 10
elif my_input == "miss":
points -= 20

print(points)

Answer 18

points_start = 100
hit_points = 10
miss_points = -20
i = 1

action = str(input('Enter action result: hit or miss. '))
while i <= 4:
if action == 'hit':
i += 1
points_start = points_start + hit_points
print(points_start)
action = str(input('Enter action result: hit or miss. '))

if action == 'miss':
i += 1
points_start = points_start + miss_points
print(points_start)
action = str(input('Enter action result: hit or miss. '))

else:
print ('Number of shots exceeded')

Answer 19

As to why input should be in the while, this is as you are to receive 4 inputs and this requires 4 input() statements.
You need the while loop to generate the input() / action = input () 4 times automatically
Just like this :-
action1 = input()
If action1 == "hit":
..
..
action4 = input()
If action4 == "hit":
..
..
But this:
while i <= 4:
action = input() #action1 - 4
..
replaces it.
(Note :-
1. I did not complete the code as the other parts/logic has been in other posts/comments - you could just fill it in the dotted (..) positions
2. If you must put input outside the loop it must be four inputs or must split an imputed text of four text if any i.e the user must type the four "hits" / "misses" at once.)

Answer 20

shots = 4
score = 100

while shots > 0:
result = input()
if result == "hit":
score +=10
shots -=1
elif result == "miss":
score -=20
shots -=1
print(score)