If we use %d in printf to print a float variable than what it print in c ?

Question

main()
{
float a=3.8;
printf("%d",a);
}

Answer 1

It's because the binary representations of the floating point number and it's corresponding integer (when properly cast) are different.

Answer 2

Don't use a format string in printf to cast one type to another unless their internal binary representations are the same.

Answer 3

But it gives 0

Answer 4

Strange... It gives 1342327848 without <stdio.h> and -773259752 with <stdio.h> in SoloLearn C Playground...
So, the compiler does not convert, it just views data as int and not float.

Answer 5

Ayush Gupta
https://stackoverflow.com/questions/2398791/how-is-conversion-of-float-double-to-int-handled-in-printf

Answer 6

%d is double precise float therefore won't work because you data type is a float it's recommended to use the%f (float) data type, so it will go like this 👇👇
#include <studio.h>
int main()
{
float a=3.8;
printf("%f",a);
}

Try it

Answer 7

get my bad must have been a confusion thanks for clarifying

Answer 8

Rick Sanchez (C-137), "%d" format specifier is for integer (<int>). Double-precise float (<double>)'s format specifier is "%lf" (first letter is small L).
https://www.sololearn.com/learn/C/2914/ page 3