LETTER COUNTER

Question

Given a string as input, you need to output how many times each letter appears in the string.
You decide to store the data in a dictionary, with the letters as the keys, and the corresponding counts as the values.
Create a program to take a string as input and output a dictionary, which represents the letter count.

Sample Input:
hello

Sample Output:
{'h': 1, 'e': 1, 'l': 2, 'o': 1}

Please help me to solve this problem.

Answer 1

P.SAI SRI RAM - CODE HERO Check this one out.
https://code.sololearn.com/cRMwJkdnCHU5/?ref=app

Answer 2

Show your attempt first. Then we'll help you to correct it.

Answer 3

text = input()
dict = {}
for char in text:
counts = text.count(char)
dict[char] = counts
print(dict)

Answer 4

P.SAI SRI RAM - CODE HERO Try this

https://code.sololearn.com/cebXGf11Gq58/?ref=app

Answer 5

Don't forget about return in the function

Answer 6

You can try to revise this:
https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2457/

Answer 7

Thanks all of you!!!!!

Answer 8

K.S.S. KARUNARATHNE you are the best!

Answer 9

https://code.sololearn.com/c6T30ieQcUx5

Add pairs to the dictionary using the "get(key [, default])" function, which looks up the key [i] (the letters at, which you want to add). If it is not, adds a pair, key = letter [i] with a default value = 0 (instead of "None" so that you can do mathematical operations) and append to the value 1 (+1). If the key is already in the dictionary, just adds 1 (+1) to the value.

>>>
text = input()
dict = {}

for i in text:
dict[i] = dict.get(i,0) + 1

print(dict)

Another way:
>>>
text = input()
dict = {a:b for a in text for b in str(text.count(a))}

print(dict)

Answer 10

Try this
text = input()
dict = {}
for letter in text:
dict.__setitem__(letter,text.count(letter))
print(dict)

Answer 11

That all

Answer 12

I was completely stumped on this project as well, thanks!

Answer 13

text = input()
dict = {}
#your code goes here
def dicting(text)
for char in text:
if char not in text:
dict += ch

Answer 14

text = input()
dict = {}
for char in text:
if char not in dict:
dict[char]=1
else:
dict[char] += 1

print(dict)

Answer 15

text = input()
dict = {}
for x in text:
dict[x] = dict.get(x,0)
if x in dict:
dict[x] += 1
print(dict)