Is this code right? It's a code from Android studio, i don't understand what's the function of activeplayer=1????

Question

public class MainActivity extends ActionBarActivity {

// 0 = yellow, 1 = red

int activePlayer = 0;

public void dropIn(View view) {

ImageView counter = (ImageView) view;

counter.setTranslationY(-1000f);

if (activePlayer == 0) {

counter.setImageResource(R.drawable.yellow);

activePlayer = 1;

} else {

counter.setImageResource(R.drawable.red);

activePlayer = 0;

}
}

Answer 1

Well, I think the code is correct. There is a button or so whose onclick() maybe set as the dropIn() function. That moves the ImageView down and changes its color to yellow or red depending on the integer variable 'activePlayer'.

Answer 2

Can you tell what exactly should be done by this code?

Answer 3

That's it. When user touches for the first time, 'activePlayer' is 0 meaning yellow color is set and 'activePlayer' is set to 1. For the next touch, 'activePlayer' is 1 meaning red color is set and 'activePlayer' is again set to 0.

Answer 4

but what's the use of 1 , I am writing same code but ain't getting same results as instructor 😥
yeah onclick is set to dropIn

Answer 5

it's a tic tac toe game's code , when a user touch screen it should show yellow image then red image then yellow , like that
but what my code is doing, showing only yellow images , no red image

Answer 6

yeah that's correct only problem is when I enter this code on my Android studio only yellow colour is showing no red color at all

Answer 7

can someone tell me?