Fill in the blanks to create a method that returns the minimum of the two parameters. public int minFunc(int n1, int n2

Question

Fill in the blanks to create a method that returns the minimum of the two parameters.
public int minFunc(int n1, int n2

{
int min;
if (n1 > n2)
min =

;

min = n1;

min;
}

Answer 1

public int minFunc(int n1, int n2)
{
int min;
if (n1 > n2)
min = n2;
else
min = n1;
return min;
}

Answer 2

public int minFunc(int n1, int n2)
{
int min;
if (n1 > n2)
min = n2;
else
min = n1;
return min;
}

Answer 3

public int minFunc(int n1, int n2
)
{

int min;

if (n1 > n2)

min =
n2
;

else

min = n1;

return
min;

}

Answer 4

import java.util.Scanner;

//your code goes here

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(Converter.toBinary(x));

}

}

public class Converter {
public static String toBinary (int x){
String binary="";
while (x>0){
binary= (x%2)+binary;
x = x/2;
}
return binary;
}
}

Answer 5

Fill in the blank to define a method that does not return a value.
public calc()

Answer 6

public int minFunc(int n1,int n2 ;){
int min;
if(n1>n2) min=n2;
else min=n1;
return min;
}

Answer 7

https://code.sololearn.com/W7C57ghNgV20/?ref=app

Answer 8

public int minFunc(int n1,int n2){
int min;
if(n1>n2) min=n2;
else min=n1;
return min;
}

Answer 9

public int minFunc(int n1, int n2)
{
int min;
if (n1 > n2)
min =n2;
else
min = n1;
return min;
}