How can I make a multiplication table by this way

Question

multiply = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
for i in multiply:
b = i * 1
c = b + 1
c = b
v = "2 " + "* " + str(i) + " = " + str(c)
print(v)

Answer 1

This will make a table.
I'm using range(1, 13) instead of your multiply variable because it'll work in a similar way with less code.

for i in range(1, 13):
row = ''
for j in range(1, 13):
b = i * j
b = str(b) # convert number to base 10 string.
b = ' ' * (4 - len(b)) + b # add enough spaces to line up columns.
row += b
print(row)

If you run locally, it should line up the columns. Sololearn's Code Playground Python codes won't line up because it uses a different font and doesn't recognize consecutive spaces differently than a single space.

Answer 2

Muhammad Abdulmalik
multiply = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
for i in multiply:
c=2*i
v = "2 " + "* " + str(i) + " = " + str(c)
print(v)

Answer 3

Firstly, you can just use for i in range(1,12), instead of the set, as it will do the exact same thing. Secondly, if you want to have it for all the numbers 1-12 times all numbers 1-12, then I would recommend using a nested loop with a for j in range(1,12) straight after the first for loop. Then replace b=i*1 with b=i*j, and that will go through everything. That
leaves the two c variable definitions needless. Now we have the multiplied numbers (i & j) and the answer (b). Format that how you wish, and there we go. It is a bit inefficient to go through all cases with addition, so I would recommend this multiplication in nested loops. You were close! Just a bit of formatting needed and it will be brilliant!