*args in python

Question

The given code defined a function called my_min(), which takes two arguments and returns the smaller one.
You need to improve the function, so that it can take any number of variables, so that the function call works.
def my_min(x, y):
if x < y:
return x
else:
return y

print(my_min(8, 13, 4, 42, 120, 7))

Answer 1

faster approach

def myfunc(*args):
return min(*args)
print(myfunc(1,2,3,4))
print(myfunc([1,2,3,4]))

Answer 2

def my_min(*args):
minval = args[0]
for num in args:
if num<minval:
minval=num
return minval
print(my_min(8, 13, 4, 42, 120, 7))

Answer 3

how about this it worked;
def my- min(x, y, *args):
return min (args)
if x < y:
return x
else:
return y
print(my-min( 8, 13, 4, 42, 120, 7))

Answer 4

Look I have following solution it may help you.

def my_min(x, *args):
if len(args) == 1:
if x < args[0]:
return x
else:
return args[0]
y, *args = args
if x < y:
return my_min(x, *args)
else:
return my_min(y, *args)

print(my_min(8, 13, 4, 42, 120, 7))

It's a recursive way of finding minimum value

DHANANJAY

Answer 5

You should add the language name in tags while asking a question.

Answer 6

def myFunc(*args):
...

will populate args with a list containing all non keywords args.

you should just find min value of this list and return it ;)

Answer 7

AssasinStudent
if OP have to implement a my_min() function, he's probably not allowed to use min() built-in...
and if he could, shorter would be:

my_min = min

anyway, if you give complete solution to OP, he will learn nothing appart copy-pasting without understanding ^^

Answer 8

python

Answer 9

ya thanks

Answer 10

Agree. Giving hints to an OP rather than a complete solution is recommended in this section.

Answer 11

Slution:

def my_min(*args):
return min(args)

print(my_min(8, 13, 4, 42, 120, 7))

Answer 12

Why it doesn't wok ?
def my_min(x, *args):
for y in args:
if x < y:
return x
else:
return y

print(my_min(8, 13, 4, 42, 120, 7))

Answer 13

def my_min(*args):
return min(args)

print(my_min(8, 13, 4, 42, 120, 7))

Answer 14

def my_min(x,*args):
for i in args:
if x < i:
res = x
else:
res = i
return res

print(my_min(8, 13, 4, 42, 120, 7))

Who can explain why it's not work?

Answer 15

Truc Tran

Above code will not work to find minimum value

It will always compare with first value (means x) during the loop

Here, it is 8, so it will always return minimum value between first value and last value in case of your code it will return 7

Since, between 8 and 7 minimum value is 7

Thanks for your concern

DHANANJAY PATEL

Answer 16

Oh I understand now. Thank you so much

Answer 17

@DHANANJAY PATEL
I understand your comment why it wouldn't work, because it will only compare with the first digit... However, that was the question of the assignment. If not, the assignment was poorly set up!! (... which takes two arguments and returns the smaller one....)

Punctuation is key!!

Answer 18

which language?