Write a function, named "convert", that takes a single argument, a string (char pointer/array). C language

Question

Write a function, named "convert", that takes a single argument, a string (char pointer/array). The function should modify the string so that all single quote characters are replaced with double quotes.
2 input cases:

1 #include <stdio.h>
2 #include <string.h>
3 void convert(char * string);
4
5 char string[] = "'abc'def\"'";
6 printf("\nStart = %s\n", string);
7 convert(string);
8 printf("End = %s\n", string);
9 assert(strcmp(string, "\"abc\"def\"\"") == 0);
10
INPUT OF THE TEST CASE

1 #include <stdio.h>
2 #include <string.h>
3 void convert(char * string);
4
5 char string[] = "My name is 'Josh'! \"Scare Quotes\"";
6 printf("\nStart = %s\n", string);
7 convert(string);
8 printf("End = %s\n", string);
9 assert(strcmp(string, "My name is \"Josh\"! \"Scare Quotes\"") == 0);

Al up code is my try and complete on it, please
Write it as a code to be more clear

Answer 1

void convert(char *s)
{
while ((s = strchr(s, '\' '))
*s = ' " ';
}

s = strchr() will jump to any singlequote in the string and set it to a double quote. but if there is no singlequote it will be NULL and it exits the loop.

Answer 2

Damyian G Does it mean that the function searches for the quotation mark and then stops, or must a stop condition be set?

Answer 3

yeah, it searches for singlequotes and returns a pointer to that location in the string. that's why *s = ' " ' will set that char to a double quote. the stop condition is set when strchr() returns NULL (end of string or no more single quotes).

Answer 4

Damyian G alright
please check my code

void convert(char * string)
{
for(*string; *string!='/0'; *(string++))
{
if(*string=='\'')
*string='"'; }
}
what is wrong here?

Answer 5

the null byte should be '\0' instead of '/0', but also *string and *(string++) will not do anything so if you want you can leave that empty.

for ( ; *string != '\0'; string++)

*string will return the character of the string where that string pointer is in memory, but you dont need to get the character to increase the pointer (if that makes sense).