Help please

Question

I’ve been stuck on this question for weeks. Can anyone help?

The program you are given takes 5 numbers as input and stores them in an array.
Complete the program to go through the array and output the the sum of even numbers.

Sample Input
10
890
15
3699
14

Sample Output
914

Hint
An integer is even if it is divisible by two, so it means that n number is even if n%2 equals 0.

What I have so far:

static void Main(string[] args)
{
int[] numbers = new int[5];
int count = 0;
while (count <5)
{
numbers[count] = Convert.ToInt32(Console.ReadLine());
count++;
}
//your code goes here
int x = 0;
foreach(int sum in numbers)
{
if (sum % 2 == 0)
{
x += sum;
Console.WriteLine(x );
}

Answer 1

Brent Tyson

Print x outside the loop

Answer 2

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
int[] numbers = new int[5];
int count = 0;
int sum = 0;
while (count <5)
{
numbers[count] = Convert.ToInt32(Console.ReadLine());
count++;
}
//your code goes here
for (int i=0;i<numbers.Length;i++)
{
if(numbers[i]%2==0) sum +=numbers[i];
}
Console.WriteLine(sum);

}
}
}

Answer 3

🅘🅜 🅰🅹 !!! thank you. it worked.

Answer 4

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
int[] numbers = new int[5];
int count = 0;
while (count <5)
{
numbers[count] = Convert.ToInt32(Console.ReadLine());
count++;
}
//your code goes here
int x = 0;
foreach (int sum in numbers)
{
if (sum % 2 == 0)
{
x += sum;
}
}
Console.WriteLine(x);

}
}
}

Answer 5

class Program
{
static void Main(string[] args)
{
int[] numbers = new int[5];
int count = 0;
while (count <5)
{
numbers[count] = Convert.ToInt32(Console.ReadLine());
count++;
}
//your code goes here
int sum = 0;
foreach (int i in numbers)
{
if(i % 2 == 0)
{
sum = sum + i;
}
}
Console.WriteLine(sum);
}
}