My code wont execute

Question

Im having issues with writing this properly since the lesson on multiple exceptions did not teach me how to write other exceptions besides basic ones.

import java.util.Scanner;
import java.util.InputMismatchException;

public class Main
{
public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

try {
int num1 = scanner.nextInt();
int num2 = scanner.nextInt();
/*
1. Еrror: division by zero
2. Error: wrong value type
*/
//your code goes here
int divide=num1/num2;
}
catch(ExceptionType1 e1)
{
throws ArithmeticException
{
if(num1==0||num2==0)
{
throw new ArithmeticException("Error: division by zero");
}
}
}
catch(ExceptionType2 e2)
{
throws InputMismatchException
{
if(num1!=(int)num1||num2!=(int)num2)
{
throw new InputMismatchException("Error: wrong value type");
}
}
}
}
}

Answer 1

Serana Zentha

There is no ExceptionType1 and ExceptionType2 exception.

To catch multiple exception you can do like this:--

try {

} catch(ArithmeticExcpetion e1) {
System.out.print("Error: division by zero");
} catch (InputMismatchException e2) {
System.out.print("Error: wrong value type");
}

Here is complete solution:
-----------

https://code.sololearn.com/cEt7aD6aCZYq/?ref=app

Answer 2

Serana Zentha

Anything which you want to throws just do after method not after catch

So there should be

int add() throws ArithmeticExcpetion, InputMismatchException {

}

https://www.sololearn.com/learning/2176/