If all stament not working

Question

Whats wrong with this code it raises syntacs eror
if all (if not b.count(i) <2 for i in c)
print ("Unique")
break

Answer 1

break should only be used inside loops...

anyway, what are b and c?
I guess that they are iterables defined before in your code?

Answer 2

also you must put colon (:) at end of 'if' line...

Answer 3

even after adding the colon still not working the problem is syntax error

Answer 4

have you also removed the 'break'?

Answer 5

Would the break stop it from raising the syntax error
It also says the first line is cousing the error.

Answer 6

oh, excuse me... you don't need the 'if' inside the all parenthesis:

if all(not b.count(i) < 2 for i in c):
print("Unique")

however not sure that your logic is right...

you might also wrap condition inside parenthesis:

if all(not (b.count(i) < 2) for i in c):
print("Unique")

to make obvious what to apply 'not'... or simply do:

if all(b.count(i) < 2 == False for i in c):
print("Unique")

Answer 7

You right i didnt check if my logic is write i wanted to know how to use the if all statement .
I will fix the logical problems that i have .
At the end you have been of a great help so THANK YOU VERY MUCH and have a nice day .

Answer 8

You can also simplify the condition to

if all(b.count(i) >= 2 for i in c):