What is the mistake for this timer code in C++? When I run the code, the "beep" gets displayed at the end.

Question

#include <iostream>
using namespace std;

int main() {
int n;
int b ;
cin >> n;

//your code goes here
while (n>0) {
cout << n << endl ;
n-- ;
}
b = n % 5 ;
if (b = 5) {
cout << "Beep" ;
}

return 0;
}

Answer 1

Hey Kruti
You have to change just to lines of code.
- place these two lines
" n--;
} "
after the "beep" line.

Answer 2

You can't use assignment operator in if conditions

Answer 3

So what will be the correct code?

Answer 4

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
while(n>=1)
{
if(n%5==0){
cout<<n <<"Beep"<<"\n";}
else{
cout<<n;
}
n--;
}

return 0;
}

Answer 5

These are some necessary changes that you should bring in your code

Answer 6

Ok thanks :) I got it now

Answer 7

Kruti

You can use do while loop here. First print number and then check if number is divisible by 5 if yes then print Beep.

do {
cout << n << endl;

if (n % 5 == 0)
cout << "Beep" << endl;
n--;
} while (n > 0);