If and not if question

Question

I want to know if I can ever get this first line to be excuted and why is it not. Please explain thanks

If not true:
Print("1")
Elif (1+1==3):
Print("2")
Else:
Print("3")

Here which statement is the first pointing to.
And this is shown as error. I expected since the whole statement is gonna be false and the second statement doesn't run the first should run and the output will result in printing 1 but that is not the case. Can somebody explain how this works? Thanks

Answer 1

there’s an error because you have used capital letters wrong. now it should work:

if not True:
print("1")
elif (1+1==3):
print("2")
else:
print("3")

Answer 2

Ok, first of all "E" in "Elif" & "Else" should be "IN LOWER CASE" is "elif" & "else".

Now, In your code first "if" statement will be always "false" because its "not true".

Then it will come to your "elif" statement, which is also false as (1+1 == 3) will return "false".

Then your "else" statement will be executed.

so it will print 3.

Answer 3

So there's no way to make the output print 1?

Answer 4

No with "not true" its not possible
For that it should be "true" or "not false".

"not true" will alway return "false"
Therefore if statement will not be executed.