Can anyone find out mistake in this program? And please help me understand the logic of this code!(solved)

Question

#include <stdio.h>

int main() {
int n,orginal,reversed,reminder;
printf("enter the number that you want to check whether a palindrome");
scanf("%d",&n);
orginal=n;
while(n!=0){
reminder=n%10; reversed=reversed*10+reminder;
n/10;
}
if(orginal=reversed)
printf ("it is a palindrome");
else
printf ("it is not a palindrome");

return 0;
}

Answer 1

Explanation with an example:

reversed = 0
original = 1234

Inside the loop:

1.
remainder = 4
reversed = 0*10+4 = 4
n=123

2.
remainder = 3
reversed = 4*10+3 = 43
n=12

3.
remainder = 2
reversed = 43*10+2 = 432
n=1

4.
remainder = 1
reversed = 432*10+1 = 4321
n=0

5. n=0
exit loop

1234 != 4321

Therefore its not a palindrome

Answer 2

Thank you so much!
Now I understood the logic!
I've been struggling to get this logic!
Even my sir couldn't make it clear though he explained 3 times!
Thatswhy I love this community:)Infinity

Answer 3

reversed has not been initialised to 0 in the beginning

Answer 4

Ya I corrected it after realising logic!
Thx:)Infinity

Answer 5

Learner🎖

And also there should be double equal (==) for comparison

Single equal (=) use for assignment.

Answer 6

I realised there is another error: It should be n=n/10

Answer 7

#include <stdio.h>

int main() {
int n,orginal,reversed,reminder;
printf("enter the number that you want to check whether a palindrome\n");
scanf("%d",&n);
orginal=n;
while(n!=0){
reminder=n%10; reversed=reversed*10+reminder;
n=n/10;
}
if(orginal==reversed)
printf ("it is a palindrome");
else
printf ("it is not a palindrome");

return 0;
}

I rectified them and it's working now!
Lemme know if I'm still doing any mistake with this code!Xusanov Bexruz

Answer 8

Thank you!
Can you help me understand the logic plz?🅰🅹 🅐🅝🅐🅝🅣 The future is now thanks to science

Answer 9

Learner🎖 👍

Answer 10

You have a lots of mistakes