How i code in python by using [if statement]

Question

I donot get code by using [if statement]

Answer 1

Devender singh

Try do it :

n = int(input(" "))

if n == 10:
print ("2")
else:
print ("1")

The motive of is printing the else is why we dont putted the int,and he confused thinked of it was a sting

Happy coding 🤗🇧🇷

Answer 2

Devender singh in your code--

example :

n = input(" ")

if n == 10:
print ("hi")
else:
print ("Hello")

the if condition will be true and executed when and only when you will put n=10, except n=10 no value of n will make the if condition true. So for different value of n else condition will be executed and you will get" Hello" as an output.

Hope things will be clear now👍👍

Answer 3

N = input (" ")

if N == 1:
print ("Its equal 1")
else:
print ("2,3,4,5,6...")

Answer 4

🇨 🇦 🇹  🦊 i enter your code

n = input(" ")

if n == 10:
print ("hi")
else:
print ("Hello")

When i enter input less than 10 or greater than so it show hello output
But when i enter 10 then it also show hello but why

Answer 5

I will share my code
https://code.sololearn.com/cJD54sC82lPJ/?ref=app

Answer 6

When n = 10
output show hi but it not show it show hello

Answer 7

Just make sure you put a collon (:) at the end of the statement also keep an eye on indentation.

Answer 8

Please explain in detail

Answer 9

My code want idented block i do not know what mistake i do in code please give me correct of it

https://code.sololearn.com/cr4jnePssMDA/?ref=app

Answer 10

Devender singh

You have to tab the print in if

the else have to be togheter with if

example :

n = input(" ")

if n == 10:
print ("hi")
else:
print ("Hello")

Answer 11

Devender singh show your code

and if you dont understad the if statemente see him again in the lessons

Answer 12

Devender singh

the motive of the output is hello is :

the if is saying N is EQUAL of 10,if he be greater or less,will print the else's print

Answer 13

👍

Answer 14

🦊 Cᴀᴛ ᴄᴜᴛᴇ 
See my under code is it right it give only one output:

https://code.sololearn.com/cUIexbYdj3yi/?ref=app