why I am unable to run the scanf() function in c?

Question

it is not running in the c programming language. I am unable to understant how so plzz tell me about that.

Answer 1

Hey Archit Kar
Use address-of operator (&) to store variable !
Ex: scanf("%c",&firstname);

Answer 2

You need to store the name in an array of chars.

Answer 3

Mahmoud 'Carbon' Saghraoui are you sure about that char[] declaration? I think it has to have fixed size, so you must declare size of that array, or make char pointer to allocate memory dynamically

Answer 4

Show your code to find error and help you with perfect solution👍

Answer 5

it does, please post your code

Answer 6

Using sololearn app? 😢

Answer 7

correct, what output did you expect?

Answer 8

I don't see any mistakes there, you may not understand your own code so let me explain it for you.

-----------------------------
char firstname[]; <-- Declared a variable, i've added the '[]' keep 'em

printf("what is your name? \n"); <-- This prints 'what is your name'
scanf("%s", firstname); <-- Takes the input of the server
-----------------------------

If you want to print the name after the input was taken then you can do
printf("Your first name is: %s", firstname);

Answer 9

ok thanks

Answer 10

include header file...
#include<stdio.h>

Answer 11

If still it's not working plzz send the codes!!

Answer 12

thnx bro

Answer 13

my code is:-

char firstname;

printf("what is your name? \n");
scanf("%s", firstname);

but the output is coming.
what is your name?

Answer 14

used may not used the library function stdio.h