Fill in the blanks to declare an array of void pointers to x1, x2 and x3 and print them using the pointers.

Question

int x1 = 42;

float x2 = 3.14;

char x3 = 'a';

void* arr[] = {&x1, &x2, ---- x3};

---------("%d %f %c",

*(( ------ *)arr[0]),

( (-------- *)arr[1]),

*(( ------- *)arr[2]));

Answer 1

int x1 = 42;

float x2 = 3.14;

char x3 = 'a';

void* arr[] = {&x1, &x2, &x3};

Printf ("%d %f %c",

*(( int *)arr[0]),

*(( float *)arr[1]),

*(( char *)arr[2]));

Answer 2

int x1 = 42;

float x2 = 3.14;

char x3 = 'a';

void* arr[] = {&x1, &x2, &x3};

Printf ("%d %f %c",

*(( int *)arr[0]),

(( float *)arr[1]),

*(( char *)arr[2]));

Answer 3

this is Q&A DISCUSSION section bro , post this to " feed " section !

Answer 4

All is correct except for (Printf ("%d %f %c",
)
write printf in lower case

Answer 5

What is the output of the following code snippet?

int x1 11, x2 22, x3 = 12; =

x1 = x2++;

x2 = -x3;

x3 = x1+x2+x3+++x2++;

cout << x1 << x2 << x3;

(a) 221255

(b) 221155

(c) 221256

(d) 221156