Am I doing the Try/Catch exercise correct

Question

I am doing this Try/Catch exercise and not sure if I am doing this right. I know it's looking for out of bounds inputs but was wondering if a for loop was needed for this as I referred to another example. I am passing all cases except for one. Help me if able to please

import java.util.Scanner;

public class Main
{
public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);
int choice = scanner.nextInt();

String[] categories = {"PCs", "Notebooks", "Tablets", "Phones", "Аccessories"};

//complete the code
try {
int a[] = new int[5];
for (int i = 0; i < 5; i++){
if(choice == i){
System.out.println(categories[i]);
}
}

} catch(Exception e) {
System.out.println("Wrong Option");
}
}
}

Answer 1

Update to this issue. I had to simply increase the iteration range in the for loop

import java.util.Scanner;

public class Main
{
public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);
int choice = scanner.nextInt();

String[] categories = {"PCs", "Notebooks", "Tablets", "Phones", "Аccessories"};

//complete the code
try {
int a[] = new int[5];
for (int i = 0; i <=7; i++){
if(choice == i){
System.out.println(categories[i]);
}
}

} catch(Exception e) {
System.out.println("Wrong Option");
}
}
}

Answer 2

My answer Working

try {
// Attempt to access the element at index 'choice'
String selectedCategory = categories[choice];
System.out.println(selectedCategory);
} catch (ArrayIndexOutOfBoundsException e) {
// Handle the case where 'choice' is out of array bounds
System.out.println("Wrong Option");
} catch (Exception e) {
// Catch any other unexpected exceptions
System.out.println("Something went wrong");
} finally {
scanner.close(); // Ensure scanner is closed to prevent resource leak
}
}
}