+ 1
Hi guys... What do I have to do to this program if I want to check if 2 or more elements are in the array. Let's say 12 n 36?
public class Program { public static int idx(int[]arr) { int i = 0; while (i<arr.length) { if(arr[i]==10) return 1; i++; } return -1; } public static void main (String []args){ int[]arr1={12,9,5,2,36,8,54}; System.out.println(idx(arr1)); } }
2 ответов
+ 2
public class Program {
public static int idx(int[] arr, List<Integer> numbers) {
int check = 0;
for (int i = 0; i < arr.length; i++) {
if (numbers.contains(arr[i])) {
check++;
if (check >= 2) {
return 1;
}
}
}
return -1;
}
public static void main(String[] args) {
List<Integer> numbers = new LinkedList<Integer>();
numbers.add(10);
numbers.add(12);
numbers.add(36);
int[] arr1 = {12, 9, 5, 2, 10, 36, 8, 54};
System.out.println(idx(arr1, numbers));
}
}
+ 1
it's supposed to return 1 if an element is available. ryt now it's checking if 10 is available in the while loop which returns -1 but if I try to check for two elements it returns an error.