Fruit Vending machine challenge

Question

I’ve been stumped by that problem. Can someone help so I could figure out how to use the list function that way. Im referring to the fruit vending machine challenge in python where user inputs number and a fruit name is shown. 7 fruits.

Answer 1

fruits = ["apple", "cherry", "banana", "kiwi", "lemon", "pear", "peach", "avocado"]
num = int(input())
#your code goes here
if num = 0:
print(fruits[0])
elif num = 1:
print(fruits[1])
elif num = 2:
print(fruits[2])
elif num = 3:
print(fruits[3])
elif num = 4:
print(fruits[4])
elif num = 5:
print(fruits[5])
elif num = 6:
print(fruits[6])
elif num = 7:
print([fruits[7]])
elif 0> num > 7:
print("Wrong number")

Answer 2

Please show me your code first. I can help with that, but I need to understand your code first.

Answer 3

0 > num > 7

is shortcut for:

0 > num and num > 7

and is not possible, as 0 > 7 is false...

you should separate it in two condition linked by a OR conditional operator:

0 > num or num > 7

however, you doesn't need all this verbose if..elif stuff: as said by David Ashton "you need to print fruits[num]"... by using if..else:

if 0 > num or num > 7:
print("Wrong number")
else:
print(fruits[num])

... or simply:

if 0 <= num <= 7:
print(fruits[num])
else:
print("Wrong number")

Answer 4

You can even boil it down more:
print(fruits[num] if num < 8 else "Wrong number")
Assuming negative numbers will not be input.

Answer 5

This works fine and captures negative numbers:

fruits = ["apple", "cherry", "banana", "kiwi", "lemon", "pear", "peach", "avocado"]
num = int(input())
#your code goes here

if num < 0:
print('Wrong number')
elif num <= 7:
print(fruits[num])
elif num > 7:
print('Wrong number')

Answer 6

fruits = ["apple", "cherry", "banana", "kiwi", "lemon", "pear", "peach", "avocado"]
num = int(input())
#your code goes here
if 0 <= num <= 7:
print([0,1,2,3,4,5,6,7])
else:
print("Wrong number")

Answer 7

Your first print statement just prints a list of the index positions of the 7 fruit. If you want to print out the fruit at index position num, you need to print fruits[num].

Answer 8

I did this one and the program says invalid syntax on line 4

Answer 9

Ok I changed them all the = to == but there is still an error with the last line which is the equality statement.

Answer 10

Wow thanks. I knew there had to be a short concise way to code this. I was able to do the other coding challanges concisely. I guess I had a difficult time umderstanding how to use this function.

Answer 11

import java.util.Scanner;
class HelloWorld {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
String[] menu={"Tea","Espresso","Americano","Water","Hot chocolate"};

int choice = sc.nextInt();
switch(choice)
{
case 0: System.out.println(menu[0]);
break;
case 1: System.out.println(menu[1]);
break;
case 2: System.out.println(menu[2]);
break;
case 3: System.out.println(menu[3]);
break;
case 4: System.out.println(menu[4]);
break;
default:System.out.println("Invalid");
}

}
}

Answer 12

What is the error here

Answer 13

Please help me

Answer 14

I'm using this code and getting an error even though my "expected output" (Wrong Number), matches the Actual output from my code...

if num >= 0 and num <= 7:
print(fruits[num])
else:
print("Wrong Number")

I then changed it to this:
if num >= 0 and num <= 7:
print(fruits[num])
elif num < 0 or num > 7:
print("Wrong Number")

It still correctly gives "Wrong Number" with an input of 12, still incorrect according to Sololearn