Want a dynamic java code to count number of time array2 present in array1

Question

I have this static code to count, how many times array2 is present in array1, but I need a dynamic code i.e. even if I change array2 to {{10,20,30},{10,20,30}} it should give a proper count.
This is a static code:
public static void main(String[] args)
{
int array1[][]= {{10,20,30,40,50,60},{10,20,40,50,70,60},{10,20,30,40,50,60},{60,70,50,40,10,20},{80,90,70,60,10,20},{60,70,50,40,10,20}};
int array2[][]= {{10,20},{10,20}};

for (int i = 0; i < array1.length; i++)
{
for (int j = 0; j < array1[0].length; j++)
{
System.out.print(array1[i][j]+"\t");
}
System.out.println();
}

int cnt=0;
for (int i = 0; i < array1.length-1; i++)
{
for (int j = 0; j < array1[0].length-1; j++)
{
for (int k = 0; k < array2.length-1; k++)
{
for (int l = 0; l < array2.length-1; l++)
{
if((array1[i][j]==array2[k][l])&&(array1[i][j+1]==array2[k][l+1])&&(array1[i+1][j]==array2[k+1][l])&&(array1[i+1][j+1]==array2[k+1][l+1]))
{
cnt++;
}
}
}
}
}
System.out.println("\nCount for array2 present in array1 is: "+cnt++);
}

Answer 1

This should do:
https://code.sololearn.com/cGBdMNf5dTqJ/?ref=app

Answer 2

No!!! I want a count of whole 2D array in another 2D array.

Answer 3

Please run the code which I have given above. You will understand it properly. The code which I have given above is static but I want it dynamic i.e. even if I change array2[][]={{20,30},{20,40}} the output must be 1 as it is present for 1 time in array1.