Java program that checks if the given integer is even or odd

Question

I wanted a program that checks if a given array is even or odd.

Example:

If input is:
5
Output should be:
Odd

Example2:
Input:
42
Output:
even

I'm new to array, and below is what I did so far:
https://code.sololearn.com/cA172A13a199

Answer 1

visph but brianna said to use array and even he/she uses array in his/her program

Answer 2

visph 🤔 wait...what.....

He wanna check using array,but in sample I/O , I think he also don't need a Loop XD

Answer 3

I think your concept of array is not clear!

Error in line 10 , num is not an array!
Error : for taking input you have to run one more for loop

code -
https://code.sololearn.com/cNmKErl74a0U/?ref=app

Answer 4

visph correct but I think then there is no difference of using array or Just makes through loop

Answer 5

Brianna
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner input= new Scanner (System.in);
int num= input.nextInt();

if (num%2==0)
System.out.println("Even");
else
System.out.println("odd");
}

}

If you check only one number at a time then use this code

Answer 6

or take input in the same loop that you use for testing oddity ;)

Answer 7

Rishav Tiwari in this specific case, there's no need of array... so having two loops as well as having an array is unuseful ^^

anyway, you could even have to intialize an array and do a first job with the values (and most far in program use the array): in this case, the array is required, but not a specific loop to initialize it ;P

Answer 8

Rishav Tiwari yes, so we could guess that's as if he/she need to use the array later in program, so having only once loop to initialize the array and testing oddity seems reasonnable ^^