Number pattern (help to correct my code)

Question

Print the following pattern for the given N number of rows.
Pattern for N = 4
1
11
202
3003

My code-

n = int(input())
i=1

while i<=n:
j=1
while j<=i:
print(j,end='')
j=j+1

print()
i=i+1
On input of 2
Result-
My Output
1
12

Expected Output
1
11

Answer 1

n = int(input())

if n > 0:
print(1)
for i in range(1,n):
print(str(i)+"0"*(i-1)+str(i))

Answer 2

Thank you
I have tried this code and it's running perfect.
https://code.sololearn.com/cwzsY5Ht5X1u/?ref=app

Happy coding!

Answer 3

n = int(input())
i=1
while i<=n:
j=0
while j<i:
print(0 if j and j<i-1 else i-1 or 1,end='')
j=j+1
print()
i=i+1

Answer 4

I've tested both...

are you sure to have correctly copyed?

Answer 5

updated second one where I made a mistake ^^

do the ide wich you run the code run python3 or python2?

in python2, print must not have parenthesis ;)

Answer 6

also, I don't know how to specify end parameter in python2 ;P

Answer 7

what is your ide and what is exactly the runtime error message (as well as the input provided)?

Answer 8

# have you tried the other shorter code and does it produce also error?

# else try with:

n = int(input())
i=1
while i<=n:
j=0
while j<i:
if i==1:
print(1, end="\n")
elif j and j<i-1:
print(0, end="\n")
else:
print(i-1, end='')
j=j+1
print()
i=i+1

Answer 9

@visph
It's showing runtime error

Answer 10

But ide on which I am running this program is throwning error.
However on sololearn your program is running perfect.
But for an input of 2 at place of 22 output must be 11.
https://code.sololearn.com/cnMJelsbmw9i/?ref=app

Answer 11

I am using python 3.5

Answer 12

I'm using coding ninjas ide
Here is the input and output
https://ibb.co/fCFPK72

Answer 13

a=int(input('enter the number'))
for i in range(a):
if i!=1:
j=i-1
print(i,j*'0',i)
else:
print(i)
print(i,i)