How to find the next element in python list?

Question

My_list = [0, 1 , 2, 3]
for I in range (Len(My_list)):
Print(My_list[I+1], [I])

The output of this code is

1 0
2 1
3 2
indexError: list index out of range

I want to get the same output but without the list index out of range. My expected output should look like this:

0 1
2 1
3 2

How can I accomplish this and get the code to run without an error??

Answer 1

shorten the range by one

Answer 2

Describe how that expected output comes to be will you?

Answer 3

You have to write:
(len(My_list)-1)
Because lenght of list is 4, thats too long ;-)

Answer 4

Oma Falk that will not work if the first value I input is 1

Answer 5

Lothar the example you provided will iterate through 0, 1 , 2, 3

My expected output is to print numbers in pairs(next list element, list element). Can you provide a running example?

Answer 6

Karzan
I am confused... what do u want?
https://code.sololearn.com/cJ1y434AZ0Ij/?ref=app

Answer 7

,Ipang yes I am taking an input from users.

Answer 8

Just reduce the range by one and your indexing error will be sorted.

And do you want the result in below way
01
12
23