Why the sorting function is not working?Input only the numbers (decimals) is the function only checking for the first character?

Question

import java.util.*;
public class Program
{
public static void main(String[] args)
{

Scanner sc=new Scanner (System.in);
String n=sc.nextLine();
String arr[]=n.split(",");

Arrays.sort(arr);

System.out.println(Arrays.toString(arr));

Answer 1

Jayakrishna🇮🇳 and Cherrim
import java.util.*;
public class Program
{
public static void main(String[] args)
{

Scanner sc=new Scanner (System.in);
String n=sc.nextLine();
String arr[]=n.split(",");
double a[]=new double[arr.length] ;

for(int i=0;i<arr.length;i++)
a[i]=Double.parseDouble(arr[i]);
Arrays.sort(a);
for(double e:a)
System.out.println(e);
}}
//Working now

Answer 2

Your applying sort on string array. So it sort on alphabetical charecters​ sorting..

for example:

aa comes before ab
11 comes before 2

Answer 3

So how to get the desired output?

Answer 4

int[] arr?

Answer 5

Cherrim I need to convert it into double. So I don't think so there is a need of int. But I maybe wrong too. Can you please elaborate your answer?

Answer 6

What are your trying to achieve?
Sort decimal values in ascending order?

Answer 7

Cherrim yes