C #preprocessing

Question

Why the result =16?
#include <stdio.h>
#define sqr(x) x*x
int main (){
int x=16/sqr(4);
printf ("%d", x) ;
}

Answer 1

You can think of #define as "find and replace", it just substitutes an expression in the code with another.
16/4*4 = 16

You can try this:
#define sqr(x) (x*x)

Answer 2

make sure when defining macros, each reference to a variable is in parenthesis. It can lead to unexpected output
https://code.sololearn.com/c385BV6bS3gg/?ref=app

Answer 3

Thank you guys for explanation, I've got it