Lambda float

Question

How can I avoid to write tree times float before x? Os where another way?

#task: 7% tax if p <= 20 else tax free
#with lambda

Code:

p= ['2','10','80','99'] thats the input

res3 = list(map(lambda x: float(x)*1.07 if float(x) <= 20 else float(x),p))
print(sum(res3))

https://code.sololearn.com/cX8VK5NB05ZI/?ref=app

Answer 1

Angela o, those are strings. Didn't notice that. This should work:

p= ['2','10','80','99']

res3 = list(map(lambda x: x*1.07 if x <= 20 else x,[float(i) for i in p]))
print(sum(res3))

Answer 2

Logical error : 7% is 0.07 not 1.07

While convert everything to float? Inasmuch as you are multiplying by a float, you will end up with a float

Answer 3

NotAPythonNinja okay. I thought it was only the sum of the tax

Answer 4

res4 = list(map(lambda x: x *1.07 if x <= 20 else x,p))
File "file0.py", line 13, in <lambda>
res4 = list(map(lambda x: x *1.07 if x <= 20 else x,p))
TypeError: '<=' not supported between instances of 'str' and 'int'

I get these errors without float before.
Please look again, because the input is in another format. W/o float it doesnt work.