pointers are confusing me HELP!

Question

#include <stdio.h>

void func(char * data){
printf("%s",data);
}

int main() {

char payload[30] = "this is random data ...\n";
void * ptr;
ptr = &payload;

//HERE !
// i saw someone using (char *) before the name of the variable and when i tried it it gave me the same output as the function without it ... can someone tell me why he used it ?

func(ptr);
func((char *)ptr);

return 0;
}

output:
this is random data ...
this is random data ...

Answer 1

So it just a implicit and explicit typecasting, void can type cast to any type

Answer 2

To conform with function signature which accepts char* argument probably. Had you defined <ptr> as char* rather than void*, there will be no need for explicit casting on function call.

Answer 3

I don't know how to explain it to you, but I know something that can help. Thank me later ;) https://youtube.com/playlist?list=PL2_aWCzGMAwLZp6LMUKI3cc7pgGsasm2_