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Implement the below function to print the frequency of these characters b, f, j, p, v in a given string and also print the coun

Example Input: Buffet Output: b=1, f=2, others=3 Input2 : aabcdhar Output: a=3, b=1, c=1,d=1,h=1,r=1 Tried String s = "hihelloBye"; char [] c = s.toCharArray(); // char search = 'l'; int uniq = 0; boolean []b = new boolean[c.length]; for (int i = 0; i< c.length; i++) { if(!b[i]) { int count = 0; if ( c[i] == 'h') { count++; b [i] = true; } else if (c[i] == 'e') { count++; b[i] = true; } else if (c[i] == 'b') { count++; b[i] = true; } if (count == 1) { uniq +=1; } else if(count > 1) { System.out.println(c[i] + " = " + count); } } } System.out.println("Uniq: " + uniq);

31st Aug 2021, 3:00 PM
Ravikumar Chauhan
3 ответов
+ 1
Syt -> Show Your Try
31st Aug 2021, 3:11 PM
Vtec Fan
Vtec Fan - avatar
0
wait a min
31st Aug 2021, 3:13 PM
Ravikumar Chauhan
0
String s = "hihelloBye"; char [] c = s.toCharArray(); // char search = 'l'; int uniq = 0; boolean []b = new boolean[c.length]; for (int i = 0; i< c.length; i++) { if(!b[i]) { int count = 0; if ( c[i] == 'h') { count++; b [i] = true; } else if (c[i] == 'e') { count++; b[i] = true; } else if (c[i] == 'b') { count++; b[i] = true; } if (count == 1) { uniq +=1; } else if(count > 1) { System.out.println(c[i] + " = " + count); } } } System.out.println("Uniq: " + uniq);
31st Aug 2021, 3:17 PM
Ravikumar Chauhan