Safety first - java do while loop challenge

Question

I am currently stuck on the do while challenge for module 2 of java. I am unable to output just one result when a single input value has been given. Below is the code that i have written which only passes for inputs greater than 2.
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password = 1;

do{
System.out.println("Write password");
password ++;
}while(password < 3);

}
}

Answer 1

- First start the do loop.
- Take the input to the
variable password
- print the output:
"Write password"
- Check while condion:
while (password != 8819)

And I think that's it.

Answer 2

Amarjot
I hope it will pass all test cases 🙂

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password;
do{
password = read.nextInt();
System.out.println("Write password");
}while(password != 8819);

}
}

Coding Cat [Mouse searching] it's exactly what I thought..

Answer 3

This is LITERALLY the HARDEST Gosh Dang Coding Language I've ever even SEEN.... NONE of it makes sense to me and IDK if it EVER WILL..... I mean ugh I can understand RUBY and KOTLIN A LOT BETTER than this...... This is VERY DIFFICULT :( :( :( :( :( :( :( :( .....!!

Answer 4

rupali very nice. But I wont give a ready to use solution to self lerners on SL. 😞

Answer 5

//Java do while challenge - Safety first

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password;
do{
System.out.println("Write password");
password=read.nextInt();
}
while(password !=8819);
}
}

//Good luck everyone

Answer 6

Kindly share the question too... bcz I don't have enough bits to unlock this challenge 😅

Answer 7

Yeh sorry that is the problem Thank you Coding Cat. Below are the sample inputs and outputs.

Sample Input
3332
8819

Sample Output
Write password
Write password

Answer 8

Or maybe first print output, then take input, then check the condition. I think, that makes more sense.

Answer 9

Thanks Rupali it worked. I understand now what I was doing wrong. Should have had the program read the next lines in the do parentheses and the while loop being the original condition of it not equalling to 8819.

Answer 10

A board game company creates new board games every year. While all the games have different rules, they also are all similar in that they each have a name and a play() method.
We need to create 3 different games - Monopoly, Chess and Battleships. In the play() method Monopoly should print “Buy all property.”, Battleships - “Sink all ships.”, and Chess - “Kill the enemy king.”
Complete the code by implementing the getName() and play() methods inherited from abstract Game class.

Answer 11

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password;
do{
password = read.nextInt();
System.out.println("Write password");
}while(password != 8819);

}
}

Answer 12

Here's the code which satisfies all the test cases :))
" int password;
do{
password=read.nextInt();
System.out.println("Write password");
password++;
}
while(password<=8819); "

Answer 13

You're creating a bank security system. The user must insert the correct password in order to access payments.
The password is 8819.

Task
Write a program that will continuously take a password as input and output Write password, until the client inserts the correct password.