Why it shows "bad" in answer?

Question

include<stdio.h>
int main() {
float x = 2.8;
if(x==2.8) {
printf("Good") ;
}else{
printf("Bad") ;
}
return 0;
}

Answer 1

A floating point literal such as 2.8 in C/C++ by default is defined as `double` type.

The precision difference between `float` and `double` type makes it tricky when performing comparison between variables of the two types.

To overcome the comparison issue, you can explicitly tell the compiler to define the literal 2.8 as `float` by appending 'f' for the literal e.g. 2.8f. This way both <x> and literal 2.8 will both be of a `float` type

if( x == 2.8f ) // <- notice the 'f'
// more code follows ...

Answer 2

Try this

#include <stdio.h>

int main() {
float x = 2.8;
float y = 2.8 ;
if(x==y) {

printf("hell9");
}else{
printf("hello");
}
return 0;
}