Break statement in the default case

Question

Still new to C++ and its unique syntaxes, I'm wondering if it makes any difference with or without the break statement

switch (number)
{
case n:
break;
default:
break; // or not
}

Answer 1

Slick

Thank you for the explanation, have a good day!

Answer 2

If the number parameter provided isn't one of the cases, default is called. If there's no default and no match you'll get unexpected output.

Answer 3

Slick

Is the break statement needed in the default case

Answer 4

No, cause it's the final case and will break regardless. It just let's everybody know for sure.

Answer 5

Adding to Slick,
You'd still need the `break` IF the `default` case is placed in other slot but the last.

Answer 6

switch (emotion){
case 1:
System.out.println("You are happy!");
break;
case 2:
System.out.println("You are sad!");
break;
case 3:
System.out.println("You are angry");
break;
case 4:
System.out.println("You are surprised");
break;

default:
if (emotion > 4 || emotion <1 ){
System.out.println("Unknown emotion.");
}

}

}