Can anyone guide me to simplify this primitive entry level code / Rock, paper and scissors

Question

Hey everyone.

I just started learning python and made a rock, scissors and paper game by my own with my limited basic level knowledge. But I feel like the codes should be much more simple than this one.

Need your guidence to simplify.

import random

ai_list = ("rock", "scissors", "paper")
end_game = False
lose_count = 0
win_count = 0

while lose_count < 3:
ai_decision = (ai_list[random.randint(1, 3)])
user_decision = input("rock, scissors or paper ? :").lower()

while ai_decision == "rock":
if user_decision == "rock":
print(f'computer:{ai_decision}, user: {user_decision}. Draw game.')
break
elif user_decision == "scissors":
print(f'computer:{ai_decision}, user: {user_decision}. You lost.')
lose_count += 1
break
elif user_decision == "paper":
print(f'computer:{ai_decision}, user: {user_decision}. You won.')
win_count += 1
break

while ai_decision == "scissors":
if user_decision == "rock":
print(f'computer:{ai_decision}, user: {user_decision}. You won.')
win_count += 1
break
elif user_decision == "scissors":
print(f'computer:{ai_decision}, user: {user_decision}. Draw game.')
break
elif user_decision == "paper":
print(f'computer:{ai_decision}, user: {user_decision}. You lost.')
lose_count += 1
break

while ai_decision == "paper":
if user_decision == "rock":
print(f'computer:{ai_decision}, user: {user_decision}. You lost.')
lose_count += 1
break
elif user_decision == "scissors":
print(f'computer:{ai_decision}, user: {user_decision}. You won.')
win_count += 1
break
elif user_decision == "paper":
print(f'computer:{ai_decision}, user: {user_decision}. Draw game.')
break
else:
print("

Answer 1

#here is (just for reference) how I refactored your code
#if you have any doubt please let me know

from random import choice # choice randomly chooses an element from a sequence

hands = r, p, s = ("rock", "paper", "scissors")
#same as r = "rock"; p = "paper"; s = "scissors"; hands = (r, p, s)

outcomes = draw, win, lose= ("Draw game", "You won", "You lost")

counts = {win: 0, lose: 0, draw: 0}
#counts is a dictionary: counts[win] == 0 ...

def game(player, computer):
#below I take the element (player, computer) of the dictionary
#if player == r == "rock" and so does computer, than the dictionary yields
#(r, r) -> draw
return {(r, r): draw,
(s, s): draw,
(p, p): draw,
(r, s): win,
(s, p): win,
(p, r): win,
(s, r): lose,
(r, p): lose,
(p, s): lose
}[(player, computer)]
#we can actually do better (using a bit of math):
#return outcomes[hands.index(player)-hands.index(computer)]

while counts[lose] < 3:
computer = choice(hands) # randomly chooses between r, p and s
player = input("rock, scissors or paper ? ").lower()

if player not in hands:
# if what the user wrote is nither r, p or s
# than it does whatever you wanted it to do
#and then jumps to the beginning of the while-loop
...
continue

#else:
result = game(player, computer) # now result is either win, lose or draw
counts[result] += 1
print (f'{computer = }, {player = }. {result}.')

Answer 2

Thanks mate, I will practice and try to grasp the concept of this version. Appreciated!