How do I fix this?

Question

I have a problem with python. I want to make a code that recognizes the person if you type a certain thing. I put the exact same thing but it gets the "No one recognized" print instead of the "Oh.. this is (Name)". I hope I can get an answer.

Code:

user_input = input()
VDP = 229998043833
G.A = 192847102401
if type(user_input) == VDP:
print("Oh.. This is VDP!")
elif type(user_input) == G.A:
print("Oh.. That is VDP's friend!")
else:
print("I can't recognize the person!")

Answer 1

If you wanted to test for types then you would've just done like this
VDP = 229998043833
GA = 192847102401
user_input = int(input())

if type(user_input) == type(VDP):
print("Oh.. This is VDP!")
if type(user_input) == type(GA):
print("Oh.. That is VDP's friend!")
else:
print("I can't recognize the person!")

Answer 2

input() returns a string (str) type. VDP is a numerical type, as is G.A (FYI unless G is an imported value, class, or instance etc, you shouldn't use .A, maybe use G_A instead). You can either change the values of VDP and G.A to strings or convert the input() values to the correct type using int() prior to comparison.

Answer 3

When you compare the variables, also make sure that both are int or str

and G.A is not a valid variable name due to the .

Answer 4

in your case if the user inputs not only digits you will get an error, so you should handle it:

VDP = 229998043833
G_A = 192847102401
try:
user_input = int(input())
if user_input == VDP:
print("Oh.. This is VDP!")
elif user_input == G_A:
print("Oh.. That is VDP's friend!")
else:
print("I can't recognize the person!")
except:
print("I can't recognize the person!")

without "try" you can go this way:

user_input = input()
VDP = "229998043833"
G_A = "192847102401"
if user_input == VDP:
print("Oh.. This is VDP!")
elif user_input == G_A:
print("Oh.. That is VDP's friend!")
else:
print("I can't recognize the person!")