def add(x, y): return x + y def do_twice(func, x, y): return func(func(x, y), func(x, y)) a = 5 b = 10 print(do_twice(add, a, b))

Question

Please explain step by step
Which is caller here?
Explain the 3rd and 4th line ?
why in 4th line we write add(add(x,y),add(x,y)) which is function of 1st line ?
how can we write function after return statement insted of (x+y+x+y )=30?

Answer 1

see..def add(x,y): #you defined your function here.
#in which x and y are parameters.
return x+y #a return statement.
#after it not a statement will get executed.
def do_twice(func,x,y):
return func(func(x,y),func(x,y))
#another func. is defined.but,'func' is the difference.
#'func' is used as a parameter to call a func. later.
a=5
b=10 #let's skip it.
print(do_twice(add,a,b)#a function print.
#in which,do_twice is 'called'.
#and add,a,b are the arguments for parameters.
#thus,do_twice will get executed.as defined.
#return add(add(5,10),add(5,10))
#add (5,10)=15.thus,add(15,15)=30.
#we have return statement.thus,we can use this ..
#value outside the def. func. too.it will return 30
#which will print 30.
note- after 'return' statement nothing is executed.

Answer 2

No i was not asking that.
Please read carefully what i have written below

Answer 3

какието непонятные примеры кода и без обьяснения логики - удаляю приложение

Answer 4

why this func is adding the (a,b)
do_twise func (func(x,y),func(x,y))
if i remove the func
it's print result
5,10,5,10

Answer 5

Can someone help me with this
def add_it(..... ,..... )
return..........
print(add_it(5,6))
I need to fill the Voids with this y , 6, x, z, 11, 5
Thanks for everything 🙂
y , 6, x, a,11,5,

Answer 6

Maybe you're asking "Recursion"

add(add(5,10),add(5,10)
->add(15,15)
->30

OR

ans=0
for i in range(2):
ans += add(a,b)