- 1
How to solve this
You need to make a program for a leaderboard. The program needs to output the numbers 1 to 9, each on a separate line, followed by a dot: 1. 2. 3. ...
39 ответов
+ 10
Luceepher
You can also try this:
print ("""1.2.3.4.5.6.7.8.9.""")
+ 9
Luceepher
Here is with loop:
[print(str(i) + '.') for i in range(1, 10)]
+ 6
Your code will be
Print('''
1.
2.
3.
4.
5.
6.
7.
8.
9.
''')
Hope you like that
+ 5
i=1
while(i<=9):
print(i, ".", sep="")
i = i+1
# Keep learning & happy coding :D
+ 5
public class number
{
public static void main(String[] args) {
for(int i =1; i<=9; i++){
System.out.println(i+".");
}
}
}
Hope it may help.
+ 5
print("\n".join([str(i)+"." for i in range(1,10)]))
+ 3
Luceepher
Don't put space after each dot(.)
+ 3
A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟
Yeah you are right
I make it.
Thanks
+ 3
Luceepher
here is a simple way as A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ was pointing out ..
for i in [1,2,3,4,5,6,7,8,9]: print(f"{i}.")
+ 3
Try it:
for i in range(1,11):
toString = str(i)
print(toString + ".")
or
for i in range(1,11):
print(str(i) + ".")
There are more alternatives you can get. Maybe this is a way to solve it.
+ 3
I tried this one and worked cool
for i in range(1,10):
print(i,end='.\n')
Also this:
Print('''1.
2.
3.
4.
5.
6.
7.
8.
9.''')
+ 2
A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ here is it ☝
+ 2
for i in range(1, 11):
print(f"{i}.")
+ 2
In java,
for(int i = 1; i <= 9; i++){
System.out.println(i+".");
+ 2
You can do it with a loop or in a single string variable:
people = [put them in order here]
for i in range (9):
print(str(i) + ". " + people[i])
Or if u only care about 1-9:
print("1.\n2.\n3.\n4.\n5.\n6.\n7.\n8.\n9.")
When the program finds \n in a string, it will think it is a new line
+ 2
public class Program
{
public static void main(String[] args) {
for(int i=0; i<=10; i++)
{
System.out.println(i+".");
}
}
}
+ 2
Try this:
for numbers in range(1, 10):
print(f"{numbers}.")
The explication:
I make a for loop in the range from 1 to 9 (10 in the code because range subtracts 1 from the only or second number in the range parameter, that is, 10-1 is 9), the loop would be like this, but putting a print (variable_of_the_loop_for ) with id (? amount of spaces, at least 1 spacez otherwise it gives an error):
1
2
3
4
5
6
7
8
9
In order not to have to type the 9 numbers. Then I give the identification, then an f-string that is written print (f "{variable} text") in {} you put the name of the variable or operation, otherwise an error appears, then the code is print (f " {numbers}. ") the result of this would be:
1.
2.
3.
4.
5.
6.
7.
8.
9.
Hope you understand, a simpler way would be instead of f-string to use string concatenation, for example:
for i in range (1, 9):
print (numbers + ".")
Well, so far my explanation. Ask me anything.
Greetings.
+ 2
sajad rajabi
Yeah, and:
print("1.")
print()
print("2.")
...
+ 2
Philip Carlin
That's in JS, but not in Python, he/she ask that in Python.
+ 2
Why I really love Python:
print('\n'.join([
'{}.'.format(number)
for number in range(1, 10)
]))
- [number for number in range (1, 10)] is a list of numbers between 1 and 9
- '{}.'.format(number) appends a dot after each number
- '\n'.join(list) joins list items with newlines, thus putting each one in its line