0
C professional please help me I'm beginner
Output Needed Input 10 integers in the array : array[0] : 1 array[1] : 3 array[2] : 5 array[3] : 7 array[4] : 9 array[5] : 11 array[6] : 13 array[7] : 15 array[8] : 17 array[9] : 19 No Even integers Found! Odd integers Found! The Odd integers are : 1 3 5 7 9 11 13 15 17 19
4 ответов
+ 1
I fixed your code but your problem is that you put the array "9" instead of "10".
#include <stdio.h>
#define SIZE 10
int main()
{
int array[SIZE], i, f;
//printf("Input 10 integers in the array:\n");
for (i=0; i<SIZE; i++)
{
//printf("\narray[%d]: ", i);
scanf("%d", &array[i]);
//printf("%d ", array[i]);
}
f=0;
for (i=0; i<SIZE; i++) if (array[i]%2==0) {
if(f==0) {
printf("\n\nThe Even integers are: \n");
f=1;
}
printf("%d ", array[i]);
}
if (f==0) printf("\n\nEven numbers not found!");
f=0;
for (i=0; i<SIZE; i++) if (array[i]%2!=0) {
if(f==0) {
printf("\n\nThe Odd integers are: \n");
f=1;
}
printf("%d ", array[i]);
}
if (f==0) printf("\n\nOdd numbers not found!");
}
https://code.sololearn.com/cti4Y4z5yt3g
0
because they're not teaching me they only suggesting i said im begginer i dont much undestand what they're saying..
sorryyy ipost it because I thought somebody gonna solve it for me ;(